Second part |
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Mars
as photographed by the Voyager 1 space probe from a distance of 520,000
km. The triangle traced out by the four enormous volcanoes can be well
defined. The essential information of the message is coded in this triangle.
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At the same time, this could
signify that in the universe the way of thinking is uniform. If there is
some other intelligence that could think similarly to us, only it could
more along other, more advanced roads to us. Let us not be suprised, then,
if the message is not given across in a way usual to everyday life. Our
own science did not do this, either. Certain parts of the message on the
gold plaque can hardly be understood by everyday man.
That is why deserved respect
should be shown for those intelligences that have conceived their message
in a way that can be comrehended by almost everybody. The message, thus,
is similar to the thinking of man on Earth, to his geometry, his mathematics,
and yet the message that is here around us, but which we have not discovered.
It
is very important to know !!
As
to whether it is a message or not, there is no need to decide here and
now. The message is conveyed in a form, that has been checked from many
different angles, and if appraised soberly cannot be viewed as pure coincidence.
For, if the message, which was originally constructed in the plane, is
drawn onto a globe, with the given straight lines like strips of rubber
placed over the globe, the difference in length afforded by the slight
curve of the lines on the globe and the straight lines is, in our case,
so minimal that the straight lines can be used on the globe.
Later, the spherical calculations will decide on
the precise values.
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The
surface of Mars, as seen on the map of Mars prepared by the Swiss Company
Hallwag.
This is the shape to recognise. |
Begins
the deciphere.
To help visualization we will study a colored spherical map. Later we will learn that the latitudinal lines of ancient Mars vary by approximately 5-6 degrees compared to the latitudes of present time. The two black lines in the lengths being equal to. Thus, the first principles can be seen. Since we are on the equator the spherical distortion is very slight, despite the distorsion of map. This is only to move our attention to this enormous triangle form. (Hallwag, Bern). The distances are nearly real here. Let you measure please.(using a page and pen) |
Very
important !!
All the system is built on the foundation of first 3 decimal places are absolute punctual in all cases and each title is repeteated at least 3 times in other and other excution !! the calculations are made to several decimal places. The more decimals taken into consideration, the greater the change in meaning. |
A
new smaller triangle is build up. Originated from the big triangle.
30° = 1773.6 km. 15° = 886.8 km.
The B side is smaller by 10% to C side. If we examine the sides of the small triangle we see that side C is 886.8 km long. This is exactly half of one of the sides of the large triangle, and 1/24 of the equator. Similar to the white line the Jovis Tholus (uppuer) volcano is just 15° too. Showing the construction. Thus, our small triangle can not only show a connection to the large one with reference to its vertex, but it is possible that it can be worked out from the large one. Every side of the small triangle can be obtained from the circumference of Mars. Let we see the small trianle. (It is worth noting that the dielectronic factor of the vacuum starts with 885. And this could be an allusion to this, for every unit can be obtained from the metre. Despite this, 886 is not equal to 885, and this must be acknowledged) The 'A' side is smaller by 10% to the 'B' side. Now ready the small triangle. But what is the reason of it. Try we again but back. |
The NASA's denominate
of this volcano is "eye". It realy looks like that. Let it only an accident.
So we have a lower eye and an upper eye and a 'mouth' if we would like.
(Ascraeus Mons). |
The middle and lower volcano gives the 9 and 10° lines. The length of the sides increase according to the powers of 10/9, or in reverse, decrease according to the powers of 9/10. (Picture: Hallwag, Bern). 10/9=1.11111..... infinitive number and 1.1111111x 1.1111111= = 1.23456787654321 (we have the first 8 digist) |
The
earth metre = ------------------------ 1 m
The mars metre = ---------- 0.532 m The Mars diametre cca. half of earth diametre. 1 earth km = 1/0.532 kiloMars =1.879699 kM (kiloMars) The 9° line gives the 1000 unit of any globe. On
earth:1°=40000km/360°=111.111...km/1°,
On
Mars: 1°=21283/360=59.12 earth km/1°, 59.12km/1°x9°=
This is the first universal constant we found. Later we can find at least two times this 1000 unit. Remember:
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there is up a small crater.
The distance from the big crater (Ascreaus mons) is 1000 earth km .
Later we will see what iportant
this small crater. This 1000 unit is an constans to compare to the distances.
(The distance given in earth unit, because the message
directed to earth.)
I think you are tired by this number stream, but our message on the gold sheet much more numbered.
All theses results are worked out from the circumference of the globe (Mars). We also find the unit of length of 1000 to be used in construction, and this way we are always given the appropiate numbers and proportions. The starting point of the construction is this unit of 1000, after which comes the construction of the curve of 1773.6 km= (2 x R x Pi/12) and then that of the curve of 798.12km =((2 x R xPi /24)x(36/40)). In this way we get a triangle, the logical use of which helps to set down other elements of the construction.
And now in summary the results of small triangle .
Remember
to the law !!
The first 3 digits are punctual! The rations of the sides. A = (40/36)**0 = 1.00 B = (10/9)**1 = 1.11 C = (10/9)**2 = 1.23 Try to go on..... D=(10/9)**4 = 1.524 E=(10/9)**8 = 2.323 F=(10/9)**16= 5.396 We have got a spiral direction. |
The
meanings of the sides.
A =
1.00 = Sun-Earth middle distance
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This
is not enough!
The distance A=718.3 km. The Log Natural's number is e=2.7183 !!! When an engineer compute allways have to use this number. This is an universal constant. Now we can say: A=718.3 (km) = (e-2)x1000=718.3 The 'A' distance expressed by Log Naturan's number !! |
The next is an unknowledge costruction on Earth. |
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The construction is shown in this map.
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And now some 'unexplained stories'.
I must
say a few words about two peculiar formula, for it points to yet another
mystery of the cosmos. What
follows is rather incredible, so I say beforehand: one either
believes it or does
not. Either way, the numbers are reality.
In 1991 a friend of
mine phoned me up and told me that a tractor driver had
explained how during night
harvesting, one of the crew of a UFO had taken him up on
board and that these, large-eyed
individuals he was unfamiliar with had given him a lot
of numerical data. Among
things he had been told a square root formula, too.
His "statement" was recorded
on tape and I listened to this attentively right the way
through. The man - who has
since then become a friend of mine - told his story in a
rather confused and hesitand
manner.
For example, he said that:
"they talked of X squared
divided by Y cubed, and always lots of zeros, there are always 024....024....always...twenty
four...this is important they said!!"
Because it is doubtful that
he is familiar with such calculations, I decided to believe what
he had said and to examine
the accurancy of it. Thus, the formula he gave looks like
this:
X**2 / Y**3 = 0.024024024024024024024.......
If we now take X as being
the time of revolution of a planet and Y as being its greatest
distance from the sun, then
we discover that this formula express Kepler's law,
only in
an
unusual way. Well my friend certainly could
not have known this. The non terminating decimal 0.024024024024...when
referring to a given planet is the constant of the course of that planet.
It express the principle
that if the square of the time of revolution of any planet is divided
by the cube of this planet's greatest distance from the sun, this gives
the unchanging, fundamental astronomical constant
number of the given planet. When I
recognized this principle in the formula I immediately began calculating
the position of the "unknown planet". The time of revolution came out as
X = 1234 days, the obtained greatest diatsnce from the sun was Y = 398.93
million km. The
result is 0.02398 (need 0.024).
I took out my world atlas
and looked at the diagram of the solar system found on the first
pages and I was suprised to find that 398.93 million km gave a point in
the very centre of the orbit of the asteroids
between Mars and Jupiter. (
we could call it an orbit of planets of debris)
That is to say, the orbit
of the asteroid. Perhaps some planetary catastrophe occured
there at some time. Science
also assumes this. Though there is also a hypothesis that
fragments of an unformed
planet are in orbit there. I do not know, but the sentences in
question point to this orbit.
This, too, may for some reason be very important from the
point of wiev of Mars.
My friend said further:
"This is very important.
squaroot of three hundred and fifty five power five dot twenty five. They
did close my small finger to pain, to remember".
As a means of a comparison
let us see the equator of Mars expressed in three
different ways:
C1 = 21,282.963 km expressed
with "e"
(K1= (e-2)x 1000x((9/10)**2)x2x12)
C2 = 21,283.2
km the middle circumference given by NASA
C3 = 21,285.25
km as expressed by the data received in the UFO
C3 = 21,285.25 = 40
x / 10000
This is 5321312.56 cm. The
1000 kMars unit of Mars in cm .
(9°x59.12 = 532.08 km)
Well, this also makes one
think. Now back to the construction.
With the above construction completed we are given the system of the volcanoes drawn to scale. The plane construction A + B and B, gives a right-angled triangle bordered by the equator.
Now, if we cut the construction out of rubber sheet and fit it over a globe, |
All figures given are real.
The course of the construction. The messages coded in the volcanoes become
clear while working with this new grid.
Every calculation and measurement
was made using one fortieth million of the earth’s circumference, that
is, the metre. On Mars, however, a “metre” corresponds to but 0.53208 Earth
metres. We could ask why the message wasn’t based on the use of the Martian
metre. One possible answer is because the message
was meant for us here on Earth. However, the formulation is one
that can be understood universally, for all data is also expressed in degrees.
And the useing of the Sun-Earth middle distance is in Earth metres. If
the message had been formulated using only the Martian metre, then we on
Earth would have had greater difficulty in recognising the system, because
we are prone to use the anthromorphous and geocentric standards of our
own planet. It is apparent that the use terrestrial standards when positioning
the volcanoes was not the result of mere chance.
Note that in the picture
the lengths A, B and C appear in several places. Now we can see where the
distances of 798.12 km and 718.3 km, given in advance, come from. The small
triangle of the eyes gives us the scale to be used when constructing the
system of the big volcanoes. Duplication serves to reinforce that the construction
has been executed as intended, for all information is given twice, and
it also gives the scale. In addition, one of the longer sides of the triangle
(30°) is used more than once in the construction, and we come across
this length again later.
Here, a thing that is not
perceivable on the map can be seen clearly. Based on the calculation the
length A - B cross the equator at 0,0 degrees, not at the centre of the
Earth volcano. Inspite of this, the system is recognisable. Here, let me
note that on the latest NASA Mars map the lower rims of all three volcanoes
touch the -10°, 0° and +10° lines of latitude. It seems that
our decoding of the message is ahead of NASA’s appraisal of the map of
Mars prepared by it. Our space probes carry a gold plaque that shows the
structure of the solar system, and the alignment of the planets, that is
the basic astronomical data. Our space probes did not have the technology
to show the relative distances of the planets. On the gold plaque the planets
are shown as being the same distance from the sun. Now let us see how the
problem of conveying these distances can be solved more successfully.
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In
picture another little volcano with a 50-60 km radius can be noted, positioned
slightly above the upper, round eye.
The Radian-volcano. (Hallwag,Bern). |
So, this little upper volcano is at a distance of precisely 1773.6 kilometres from the Earth volcano. (30°) In other words,the 1000 unit scale to be used in the construction is given here, and here the distances are repeated for the third time. This unit of 1000 could be in metres, centimetres, feet, yards, radians, gradients whatever,only the globe must be prepared to a corresponding scale. |
That is at all time: e =
2 + (12.15° / 16.914938° ) = 2.7183 = (natural logarithm).
In essence:
D=(1000U)= *********************************************(16.914938°
long, always, yellow line )
A=(718.3U)= ****************************(12.15°
long always, see small triangle 'A' side)
A/1000unit = 12.15°/16.914938° = 0.7183 (always, see small triangle 'A' side) and e=2.7183. This value is the same at any point of the universe !! In our case: 16.914938° x 59.12 km/1° = 1000 km These two numers are coded in degrees ( we could say “chised in stone” ). in the distances “D”(30°) and “A” (12.15° and yellow line (1000 unit).
In this way the natural logarithm, one of the pillars of the cosmic world, is wins a general conception which can be reconstructed and recognised everywhere and all times. We know that on our map 1° = 59.12 km, so that by multiplying this by the given number we get the unit of distance as the desired Earth: The unit in earth kilometres = 16.914938°x 59.12km/1° = 1000 km. If the calculations seem to complicated, don’t warry, all that needs to be noted is that the 1000 km distance can be multiplied by the distance measured at 1° on the surface of a sphere of any size. A small spherical radius gives a small distance, a big spherical radius gives a big distance. For example, constructed proportionately on the surface of the earth the unit-distance would be 16.914938° x 111.111km/1°=1879.44 km. This is why the unit of 1000 on the earth alone gives 1000 km !! In other words, someone prepared the message for us !! Anyone can convert the 1000 unit distance to his own planet, but it is only to the intelligence on Earth that data really worthy of was afforded.
What is really wonderful
about it is that this same distance - as we have seen - has been worked
out for the universal values of the base number of the Natural Logarithm,
and for the radians.
( Not that I wish to frightten
the reader, but allow me demonstrate why “e”, the
“Pi” and the “radian” are so important. These three numbers are indispensabele
in electrotechnichs, mechanical rotations, radiomery, but also in expressing
the 21 cm wavelength of the hidrogen atom given in the message we sent
on the gold plaque.
Most frequently it appears in the following way: e**( j*Omega*t ). Here e=2.7183 and the Omega=2*Pi(radian) and the t = time.
Which is a very neat, universal solution. If it happens that not everything is clear, do not despair, because even I did not understand everything at first.
Countless number of times I put the whole thing aside and gave up trying. At first it was not at all the self-evident place and solution that I came across.I, too, was slave to a “geometric view of things”. I calculated everything in kilometres ontained from the dimensions of the earth. It seems that those leaving the message had counted on this. Which is why the metre system had to be used because - as we shall see - the astronomical Sun-Earth distance is also found coded there, almost exactly as it was engraved by our scientists on the gold plaque. For - the creators of the cosmic message must have thought - they are sure to calculate and depict the Sun-Earth distance using the system of measurements with kilometres that are ontained from the dimensions of the earth.
Let us see how they have
given us the coding of the Sun-Earth real distance. The length giving the
unit of 1000 is only 995.3 kilometres long if the angle is exactly 1 radian,
for it is mathematically impossible to obtain a greater accuracy with the
1773.6 km (30 degrees) value. If the angle is 0.9997 radians then the distance
of unit is exactly 1000. So the 3 digit accuracy is correct the radian
= 1. But all come to rigth if the system has an accurancy of In reality,
Astronomers use the radius of the earth’s elliptically circular orbit around
the sun to express one astronomical unit. Its value : 149.598 million kilometres.In
the following sections, this distance is taken as the middle distance of
the sun from the earth,so we know what it refers to,but what it actually
means is the average radius of an elliptic orbit.I will use the notation
AU (Astronomical Unit).
The expression “elliptically
circular” is used because this orbit is almost circular.
In our constructions and calculations the actual 149.6 million kilometre distance appears on the surface of Mars, scaled down to 702.6 km. |
This means that the Martian astronomical unit (702) is worked out from the real Sun-Earth middle distance. (149.6 million of km) |
(To put it another way, the
Sun-Earth AU has been divided by ten times the circumference of Mars. You
can read more about later).
Earth and Mars, then, are connected by a piece of real astronomical data. Time must be given to taste, enjoy and digest this finding, because it is so different, so much newer than the solutions we have been used to. |
But
let us see how this distance (702.6km) can be made use of. How can this
distance be used to convey how far the sun is from Earth or Mars?
We can see in the picture: - the
sun-earth distance (10°=1 AU)
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This means that if we take
the unit 702.69, obtained from the sun and Mars, and mark this unit on
the side of the large triangle, then at Earth and Mars we are given precise
distances, that are in accordance with celestial mechanics.
The use of the Martian astronomical
unit can be seen in the diagram.
We are given the Sun-Mercury
and the Sun-Venus proportions. Moreover, with astronomical accuracy. The
accuracy with which we measure and calculate is reflected in the accuracy
of the results we obtain.
If we measure the distance
between Sun-Venus and Sun-Mercury and divide them it is 1.868. This is
absolute punctual to the real distances ratio.
The
real Sun-Earth distance:149,530,000 km = 21,283 km x 702.6
x 10
The Mars cicumference = 21,283 The 702.6 km you saw before as a cross-section. Who would have thought that a connection between a real astronomical distance and the circumference of Mars could be shown by using the radian ? Measuring this all-telling 702.6 onto a section representing one twelfth of the circumference of Mars, Let circumference of Mars=C then (C/12)/702.6=1+1.524, we are given, with great accuracy, the real, scaled-down astronomical distances. |
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The real wonder is we can
find this thinking among the martian city too.
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All rigths by Attila Foldes